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i#7050 remove preempted instruction and memref. #7058
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05ddb8a
i#7050: reset expected read and write record counts after a kernel tr…
ivankyluk b1feaeb
Merge branch 'master' into i7050-reset-expected-read-write-record-counts
ivankyluk 0ffeb9e
Merge branch 'master' into i7050-reset-expected-read-write-record-counts
ivankyluk da6d3fa
Merge branch 'master' into i7050-reset-expected-read-write-record-counts
ivankyluk f02cd07
Merge branch 'master' into i7050-remove-preempted-instructions
ivankyluk f3ee810
Merge branch 'i7050-reset-expected-read-write-record-counts' of githu…
ivankyluk 1ede682
Adding debug to confirm aarchxx results.
ivankyluk 10c8705
Update signal_invariants.c to ignore preempted instr and memref.
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I looked back at the details and I really do not understand what is happening with this. Could you explain how this scenario occurred? I wrote some of my confusion at #7050 (comment).
Putting aside the fact that a regular asynch signal should not cause this kind of thing: if there were some real preempt from say thread relocation, why isn't raw2trace filling in the rest of the instructions in the block? How is the handler code running already? That makes it sound like raw2trace is already truncating the rest of the block and somehow solving #5790? On that note is this PR as written solving #5790?
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What is in the raw trace records? What is the instruction count for the
shl
block? What is the exact raw trace order of the branch's block PC, shl block PC, shl address, and signal marker?There was a problem hiding this comment.
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Here's the trace without the change:
Raw trace: