fix: common util func handleSingleNodeGraph

[ayu-exorcist]

comboCombined 调用 handleSingleNodeGraph 函数的前提是: 移除了 _isCombo 状态的 nodes 的个数 <= 1

layout/packages/layout/src/comboCombined.ts

Lines 93 to 104 in 3a70d63

	const nodes: Node[] = graph
	.getAllNodes()
	.filter((node) => !node.data._isCombo);
	const combos: Node[] = graph
	.getAllNodes()
	.filter((node) => node.data._isCombo);
	const edges: Edge[] = graph.getAllEdges();
	const n = nodes?.length;
	if (!n || n === 1) {
	return handleSingleNodeGraph(graph, assign, center);
	}

但是 handleSingleNodeGraph 函数内部处理时, 获取到的是包含 _isCombo 状态的 nodes.

layout/packages/layout/src/util/common.ts

Lines 10 to 43 in 3a70d63

	export const handleSingleNodeGraph = (
	graph: Graph,
	assign: boolean,
	center: PointTuple,
	) => {
	const nodes = graph.getAllNodes();
	const edges = graph.getAllEdges();
	if (!nodes?.length) {
	const result = { nodes: [] as any[], edges };
	return result;
	}
	if (nodes.length === 1) {
	if (assign) {
	graph.mergeNodeData(nodes[0].id, {
	x: center[0],
	y: center[1],
	});
	}
	const result = {
	nodes: [
	{
	...nodes[0],
	data: {
	...nodes[0].data,
	x: center[0],
	y: center[1],
	},
	},
	],
	edges,
	};
	return result;
	}
	};

这会导致使用 combo-combined 布局时, 存在某些异常->handleSingleNodeGraph 函数返回 undefined, 异常数据如下所示:

{
  nodes: [{id: 'node1'}, {id: 'node2', combo: 'combo1'}, {id: 'node3', combo: 'combo1'}],
  combos: [{id: 'combo1'}],
}

[ayu-exorcist]

这样改动可能会对其他布局造成影响, 或许这里可以将 nodes 和 edges 主动传入, 来屏蔽不同布局调用 handleSingleNodeGraph() 函数和该函数定义处数据不一致导致的问题

export const handleSingleNodeGraph = (
  nodes: Node[],
  edges: Edge[],
  graph: Graph,
  assign: boolean,
  center: PointTuple,
) => {

或者传入布局的 id, 在 handleSingleNodeGraph() 进行判断处理