Skip to content

Commit

Permalink
Get LaTeX compiling again
Browse files Browse the repository at this point in the history
  • Loading branch information
kbuzzard committed Apr 17, 2024
1 parent 783c3c9 commit 6789347
Show file tree
Hide file tree
Showing 3 changed files with 49 additions and 24 deletions.
12 changes: 6 additions & 6 deletions blueprint/src/chapter/ch02reductions.tex
Original file line number Diff line number Diff line change
Expand Up @@ -23,30 +23,30 @@ \section{Reduction to \texorpdfstring{$n\geq5$}{ngeq5} and prime}

Euler proved Fermat's Last Theorem for $p=3$; at the time of writing this is not in mathlib.

\begin{lemma}\label{p_not_three}\lean{fermatLastTheoremThree}\leanok
\begin{lemma}\label{fermatLastTheoremThree}\lean{fermatLastTheoremThree}\leanok
\discussion{16}
There are no solutions in positive integers to $a^3+b^3=c^3$.
\end{lemma}
\begin{proof}
The proof has been formalised in Lean in the FLT-regular project \href{https://github.com/leanprover-community/flt-regular/blob/861b7df057140b45b8bb7d30d33426ffbbdda52b/FltRegular/FltThree/FltThree.lean#L698}{\underline{here}}. To get this node green, the proof (or another proof) needs to be upstreamed to mathlib.
\end{proof}

\begin{corollary}\label{WLOG_p_ge_5}\leanok If there is a counterexample to Fermat's Last Theorem, then there is a counterexample $a^p+b^p=c^p$ with $p$ prime and $p\geq 5$.
\begin{corollary}\label{p_ge_5_counterexample_of_not_FermatLastTheorem}\lean{p_ge_5_counterexample_of_not_FermatLastTheorem}\leanok If there is a counterexample to Fermat's Last Theorem, then there is a counterexample $a^p+b^p=c^p$ with $p$ prime and $p\geq 5$.
\end{corollary}
\begin{proof}\uses{p_not_three, FermatLastTheorem.of_odd_primes}\leanok Follows from the previous two lemmas.\end{proof}
\begin{proof}\uses{fermatLastTheoremThree, FermatLastTheorem.of_odd_primes}\leanok Follows from the previous two lemmas.\end{proof}

\section{Frey packages}

For convenience we make the following definition.

\begin{definition}\label{Frey_package}\lean{FLT.FreyPackage}\leanok A \emph{Frey package} $(a,b,c,p)$ is three nonzero pairwise coprime integers $a$, $b$, $c$, with $a\equiv3\pmod4$ and $b\equiv0\pmod2$, and a prime $p\geq5$, such that $a^p+b^p=c^p$.\end{definition}
\begin{definition}\label{FLT.Frey_package}\lean{FLT.FreyPackage}\leanok A \emph{Frey package} $(a,b,c,p)$ is three pairwise-coprime nonzero integers $a$, $b$, $c$, with $a\equiv3\pmod4$ and $b\equiv0\pmod2$, and a prime $p\geq5$, such that $a^p+b^p=c^p$.\end{definition}

Our next reduction is as follows:

\begin{lemma}\label{Frey_package_of_FLT_counterex}\lean{FLT.FreyPackage.of_not_FermatLastTheorem}\leanok
\begin{lemma}\label{FLT.FreyPackage.of_not_FermatLastTheorem}\lean{FLT.FreyPackage.of_not_FermatLastTheorem}\leanok\discussion{19}
If Fermat's Last Theorem is false, then there exists a Frey package.
\end{lemma}
\begin{proof}\uses{Frey_package, WLOG_p_ge_5} By Corollary \ref{WLOG_p_ge_5} we may assume that there is a counterexample $a^p+b^p=c^p$ with $p\geq 5$ and prime; we now build a Frey package from this data.
\begin{proof}\uses{Frey_package, p_ge_5_counterexample_of_not_FermatLastTheorem} By Corollary \ref{p_ge_5_counterexample_of_not_FermatLastTheorem} we may assume that there is a counterexample $a^p+b^p=c^p$ with $p\geq 5$ and prime; we now build a Frey package from this data.

If the greatest common divisor of $a,b,c$ is $d$ then $a^p+b^p=c^p$ implies $(a/d)^p+(b/d)^p=(c/d)^p$. Dividing through, we can thus assume that no prime divides all of $a,b,c$. Under this assumption we must have that $a,b,c$ are pairwise coprime, as if some prime divides two of the integers $a,b,c$ then by $a^p+b^p=c^p$ and unique factorization it must divide all three of them. In particular we may assume that not all of $a,b,c$ are even, and now reducing modulo~2 shows that precisely one of them must be even.

Expand Down
48 changes: 30 additions & 18 deletions blueprint/src/chapter/chtopbestiary.tex
Original file line number Diff line number Diff line change
Expand Up @@ -48,7 +48,9 @@ \section{Results from class field theory}
\end{proof}

\begin{theorem} ("Euler-Poincar\'e characteristic) If $h^i(M)$ denotes the order of $H^i(G_K,M)$ then $h^0(M)-h^1(M)+h^2(M)=0$.
If $\mu_\infty$ denotes the Galois module of all roots of unity in our fixed $\overline{K}$, then one can define the dual Galois module $M'$ as $\Hom(M,\mu)$ with its obvious Galois action.
\end{theorem}

If $\mu_\infty$ denotes the Galois module of all roots of unity in our fixed $\overline{K}$, then one can define the dual Galois module $M'$ as $\Hom(M,\mu)$ with its obvious Galois action.

If $0\leq i\leq 2$ then the cup product gives us a map $H^i(K,M)\times H^{2-i}(K,M')\to H^2(K,\mu_\infty)$.

Expand All @@ -62,7 +64,7 @@ \section{Results from class field theory}

We now move onto the global case. If $N$ is a number field, that is, a finite extension of $\Q$,
then let $\A_N^f:= N\otimes_{\Z}\widehat{Z}$
denote the finite adeles of $N$ and let $N_\infty := N\otimes_\Q\R$ denote the product of the completions of $N$ at the infinite places, so $\A_N:=\A_N^f\times N_\infty$ is the ring of adeles of $N$.
denote the finite adeles of $N$ and let $N_\infty := N\otimes_{\Q}\R$ denote the product of the completions of $N$ at the infinite places, so $\A_N:=\A_N^f\times N_\infty$ is the ring of adeles of $N$.

\begin{theorem} If $N$ is a finite extension of $\Q$ then there are two ``canonical'' isomorphisms between the profinite abelian groups $\pi_0(\A_N^\times/N^\times)$ and $\GN^{\ab}$; one sends local uniformisers to arithemtic Frobenii and the other to geometric Frobenii; each of the global isomorphisms is compatible with the local isomorphisms above.
\end{theorem}
Expand Down Expand Up @@ -102,16 +104,18 @@ \section{Structures on the points of an affine variety.}
\begin{remark} Probably this is fine for a broader class of fields $K$.
\end{remark}

\begin{conjecture}\label{manifold_on_algebraic_variety_computation}
\begin{theorem}\label{manifold_on_algebraic_variety_computation}
If $X$ is as in the previous definition and $X\to\mathbb{A}^n_K$ is a closed immersion, then the induced map from $X(K)$ with its manifold structure to $K^n$ is an embedding of manifolds.
\end{theorem}

\begin{proof} I'm assuming this is standard, if true.
\end{proof}
\begin{corollary}\label{lie_group_from_algebraic_group}
If $G$ is an affine algebraic group of finite type over $K=\R$ or $\C$ then $G(K)$ is naturally a real or complex Lie group.
\end{corollary}
\begin{remark}

The corollary, for sure, is true! And it's all we need. I have not yet made any serious effort to find a reference for the definition or independence, although there seem to be some ideas \href{https://leanprover.zulipchat.com/#narrow/stream/116395-maths/topic/top.20space.20.2F.20manifold.20structure.20on.20points.20of.20alg.20varieties/near/431812525}{here}.

\end{remark}
\section{Algebraic groups.}

The concept of an affine algebraic group over a field $K$ can be implemented in Lean as a commutative Hopf algebra over $K$, as a group object in the category of affine schemes over $K$, as a representable group functor on the category of affine schemes over $K$, or as a representable group functor on the category of schemes over $K$ which is represented by an affine scheme. All of these are the same to mathematicians but different to Lean and some thought should go into which of these should be the actual definition, and which should be proved to be the same thing as the definition.
Expand Down Expand Up @@ -161,7 +165,7 @@ \section{Automorphic forms and representations}

Automorphic forms form a typically infinite-dimensional vector space.

\begin{definition} An automorphic form is \emph{cuspidal} (or ``a cusp form'') if it furthermore satisfies $\int_{U(N)\U(\A_N)}\phi(ux)du=0$, where $P$ runs through all the proper parabolic subgroups of $G$ defined over $N$ and $U$ is the unipotent radical of $P$, and the integral is with respect to the measure coming from Haar measure.
\begin{definition} An automorphic form is \emph{cuspidal} (or ``a cusp form'') if it furthermore satisfies $\int_{U(N)\backslash U(\A_N)}\phi(ux)du=0$, where $P$ runs through all the proper parabolic subgroups of $G$ defined over $N$ and $U$ is the unipotent radical of $P$, and the integral is with respect to the measure coming from Haar measure.
\end{definition}

The cuspidal automorphic forms form a complex subspace of the space of automorphic forms.
Expand All @@ -188,31 +192,39 @@ \section{Automorphic forms and representations}
\begin{proof} See Flath's article in~\cite{corvallis1}.
\end{proof}

As mentioned above, we only need all of this for abelian algebraic groups and for inner forms of $GL_2$ over totally real fields, where everything can be made more concrete (and in particular where I can write down concrete definitions, although this still needs to be done).
As mentioned above, we only need all of this for abelian algebraic groups and for inner forms of $\GL_2$ over totally real fields, where everything can be made more concrete (and in particular where I can write down concrete definitions, although this still needs to be done). In particular, we don't strictly speaking need all of the above, we could just cheat and deal with $\GL_2(\R)$ and $\H^\times$ separately.

\definition{}
The theorems I need are: Jacquet-Langlands for inner forms of $\GL_2$ over totally real fields,
and multiplicity 1 for these inner forms. We also need cyclic base change plus classification of image, all for totally definite quaternion algebras, and we need
automorphic induction from $\GL_1(K)$ to $\GL_2(F)$ when $K/F$ is a degree 2 totally imaginary extension. There seems to be little point formalising the statements of the theorems if we cannot yet even formalise the definition of an automorphic representation properly.

**TODO** write this properly.
\section{Galois representations}

Mention Mazur's theorem.
Ivan Farabella has formalised the definition of a compatible family of Galois
representations, modulo the existence of Frobenius elements, which has been
established by Jou Glasheen.

Then:
\begin{definition}\leanok Let $N$ be a number field. A \emph{compatible family of $d$-dimensional Galois representations over $N$} is a finite set of finite places $S$ of $N$,
a number field $E$, a monic degree $d$ polynomial $F_{\p}(X)\in E[X]$ for each finite place $\p$ of $K$ not in $S$ and, for each prime number $\ell$ and field embedding $\phi : E\to\Qlbar$ (or essentially equivalently for each finite place of $E$), a continuous homomorphism $\rho:\GK\to\GL_2(\Qlbar)$ unramified outside $S$ and the primes of $K$ above $\ell$, such that $\rho(\Frob_\p)$ has characteristic polynomial $P_\pi(X)$ if $\pi$ lies above a prime number $p\not=\ell$ with $p\not\in S$.
\end{definition}

JL,
The big theorem, which again we are far from even \emph{stating} right now, is

mult 1,
\begin{theorem} Given an automorphic representation $\pi$ for an inner form of $\GL_2$ over a totally real field and with reflex field~$E$, such that $\pi$ is weight 2 discrete series at every infinite place, there exists a compatible family of 2-dimensional Galois representations associated to $\pi$, with $S$ being the places at which $\pi$ is ramified, and $F_{\p}(X)$ being the monic polynomial with roots the two Satake parameters for $\pi$ at $\p$.
\end{theorem}

cyclic base change
\section{Algebraic geometry}

automorphic induction from GL_1(quad extn) to GL_2
We need

Galois rep associated to an auto rep,
We

Mention Mazur's theorem.

Definition of an automorphic representation for the units of a quaternion algebra over a totally real field (including situations where the algebra is split at one or two infinite places).

Shimura curves and Shimura surfaces, plus a description of their etale cohomology in terms of automorphic representations.

Classification of finite subgroups of PGL_2(F_p-bar)
Classification of finite subgroups of $\PGL_2(\overline{\F}_p)$

Moret-Bailly

Expand Down
13 changes: 13 additions & 0 deletions blueprint/src/macro/common.tex
Original file line number Diff line number Diff line change
@@ -1,7 +1,11 @@
% Put any macro needed for the project here. Those macros for both the web and print versions of the blueprint.

\newcommand{\Z}{\mathbb{Z}}
\newcommand{\A}{\mathbb{A}}
\newcommand{\Q}{\mathbb{Q}}
\newcommand{\R}{\mathbb{R}}
\newcommand{\F}{\mathbb{F}}
\renewcommand{\C}{{\mathbb{C}}}
\newcommand{\Qp}{\mathbb{Q}_p}
\newcommand{\Ql}{\mathbb{Q}_\ell}
\newcommand{\Qbar}{\overline{\Q}}
Expand All @@ -13,10 +17,19 @@
\newcommand{\GQl}{\Gal(\Qlbar/\Ql)}
\newcommand{\m}{\mathfrak{m}}
\newcommand{\GK}{\Gal(K^{\sep}/K)}
\newcommand{\GN}{\Gal(\overline{N}/N)}
\newcommand{\Kbar}{\overline{K}}
\renewcommand{\O}{\mathcal{O}}
\newcommand{\p}{{\mathfrak{p}}}
\DeclareMathOperator{\Gal}{Gal}
\DeclareMathOperator{\Aut}{Aut}
\DeclareMathOperator{\GL}{GL}
\DeclareMathOperator{\PGL}{PGL}
\DeclareMathOperator{\SL}{SL}
\DeclareMathOperator{\Spec}{Spec}
\DeclareMathOperator{\sep}{sep}
\DeclareMathOperator{\ab}{ab}
\DeclareMathOperator{\tr}{tr}
\DeclareMathOperator{\Hom}{Hom}
\DeclareMathOperator{\Frob}{Frob}

0 comments on commit 6789347

Please sign in to comment.