uncurryThis uses bind twice #51230
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aduh95
saurabhraushan
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i don't understand this line plz help |
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Answered by
aduh95
Dec 21, 2023
Replies: 2 comments
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bro, could you please paste the sample code here? This will help us understand your question better. |
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I don't know if it helps, but it used to be even more convoluted: #36866 I wouldn't worry too much if you don't understand it, no one should need to make their own |
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RedYetiDev
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I don't know if it helps, but it used to be even more convoluted: #36866
I wouldn't worry too much if you don't understand it, no one should need to make their own
uncurryThis
, if you're happy to take my word for it, just know it's equivalent toconst uncurryThis = (fn) => (this, ...args) => Reflect.apply(fn, this, args)
.