-
-
Notifications
You must be signed in to change notification settings - Fork 85
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
Calculating the bounding_box() of the Сell before and after the flatten() #188
Comments
Can you share an example where this issue happens? |
Sorry, but without being able to reproduce it locally, I can't see what the problem might be. The examples I try here all work. |
Sorry for a longtime answer.
This script gets to me different bounding_box before and after flatten() in "def make_job". |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Hello! Sorry if I'm duplicating my problem in issues. When I have a Cell with only references. And I get the bounding_box() of that Cell. Example - (x0, y0)(x1, y1). After that, I call the flatten() method and get the other bounding_box() coordinates. Example - (x0, y0)(x2, y2). Why? I repeat, Cell only has references. Maybe the calculation of bounding_box happens up to a certain level of references?
The text was updated successfully, but these errors were encountered: