Q:
如何将字符串N个一组地反序，比如将'0123456789'反序成'8967452301'？字符串长 度不限，可能包含各种字符，不限于数字。
A: bluerust 2016-07-19
x = '0123456789'
n = 2
''.join([x[i:i+n] for i in xrange(0,len(x),n)][::-1])
''.join(reversed([x[i:i+n] for i in xrange(0,len(x),n)]))import re
x = '0123456789'
''.join(re.findall('..',x)[::-1])x = '0123456789'
n = 2
''.join(map(''.join, zip(*[iter(x)]*n))[::-1])x = '0123456789'
''.join(map(str.__add__, x[-2::-2], x[-1::-2]))