We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself.
Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example:
Input: 28
Output: True
Explanation: 28 = 1 + 2 + 4 + 7 + 14
class Solution {
public boolean checkPerfectNumber(int num) {
if (num == 1) return false;
int sum = 0;
for (int i = 2; i <= Math.sqrt(num); i++) {
if (num % i == 0) sum += i + num / i;
}
sum++;
return sum == num;
}
}
- 一个数的除数在sqrt(n)左右两边应该是对称的,所以只要查找小于sqrt(n)的数并且记录其和,最后比较是否等于该数即可。