Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
class Solution {
public int addDigits(int num) {
return 1 + (num - 1) % 9;
}
}
- Input:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,...
- Output:0,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,...